My 1st post

MathJax is working: $\sin(x)$ $$ \int\limits_0^{+\infty} \frac{dx}{1 + x^2} = \operatorname{arctan}(x)\operatorname{\Biggr\rvert}\limits_{0}^{+\infty} = \frac{\pi}{2} $$

February 11, 2025 · 1 min · 14 words · Me